base (6)!(3)A
rule (x)A !(x)F[(45)&(0.6*x)B](137.5)/(0.9*x)A
rule (x)B !(x)F[(45)-(0.6*x)C](10)&(30)\(0.9*x)C<g(0.2)L>
rule (x)C !(x)F[(45)+(0.6*x)B](15)^(40)/(0.9*x)B<g(0.2)L>