/*
  * Java has support for exception-handling with 
  * a finally block
  * Java does not turn a keyboard interrupt into an
  * Exception.
*/

import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;


public class TryCatch {
     public static void main (String[] args) throws IOException {
        int number;
        while (true) {
             try {
                    BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
                    System.out.print("Enter number: ");
                    number = Integer.parseInt(in.readLine());
                    if (number == 0) break;
            }
            catch (NumberFormatException e) {
                System.out.println("Illegal number");
            }
            catch (Exception e ) {
                System.out.println("general exception");
            }
            finally {
                System.out.println("In the finally block");
            }
        }
         System.out.printf("number is %d\n", number);
    } // end main
} // end class